The formula for the area of a trapezoid with altitude k and bases m and n is . A=k/2 (m+n) solve for m..
Answer:
\(m=A\times\frac{2}{k}-n\)
Step-by-step explanation:
Given : The formula for the area of a trapezoid with altitude k and bases m and n is \(A=\frac{k}{2}(m+n)\)
We have solve for m .
Consider the given formula \(A=\frac{k}{2}(m+n)\)
Multiply both side by \(\frac{2}{k}\), we have,
\(A\times\frac{2}{k}=m+n\)
Now subtract n both side, we have,
\(A\times\frac{2}{k}-n=m\)
Thus, \(m=A\times\frac{2}{k}-n\)
Answer:
When solving for m we get \(m=\frac{2A}{k}-n\)
Step-by-step explanation:
Given: Formula for Area of trapezoid, \(A\:=\:\frac{k}{2}(m+n)\)
k is height of the trapezoid and m & n are bases of trapezoid.
We have to solve the formula for m.
Consider the formula,
\(A=\frac{k}{2}(m+n)\)
\(A\times\frac{2}{k}=m+n\)
\(\frac{2A}{k}=m+n\)
\(\frac{2A}{k}-n=m\)
\(m=\frac{2A}{k}-n\)
Therefore, When solving for m we get \(m=\frac{2A}{k}-n\)