Verified Answer :

Answer:

\(m=A\times\frac{2}{k}-n\)

Step-by-step explanation:

Given : The formula for the area of a trapezoid with altitude k and bases m and n is \(A=\frac{k}{2}(m+n)\)

We have solve for m .

Consider the given formula  \(A=\frac{k}{2}(m+n)\)

Multiply both side by \(\frac{2}{k}\), we have,

\(A\times\frac{2}{k}=m+n\)

Now subtract n both side, we have,

\(A\times\frac{2}{k}-n=m\)

Thus, \(m=A\times\frac{2}{k}-n\)

Answer:

When solving for m we get \(m=\frac{2A}{k}-n\)

Step-by-step explanation:

Given: Formula for Area of trapezoid, \(A\:=\:\frac{k}{2}(m+n)\)

           k is height of the trapezoid and m & n are bases of trapezoid.

We have to solve the formula for m.

Consider the formula,

\(A=\frac{k}{2}(m+n)\)

\(A\times\frac{2}{k}=m+n\)

\(\frac{2A}{k}=m+n\)

\(\frac{2A}{k}-n=m\)

\(m=\frac{2A}{k}-n\)

Therefore, When solving for m we get \(m=\frac{2A}{k}-n\)