Answer:
Option C \(126\ in^{2}\)
Step-by-step explanation:
we know that
The lateral surface area of the cylinder is equal to
\(LA=2\pi rh\)
In this problem we have
\(r=5/2=2.5\ in\) -----> the radius is half the diameter
\(h=8\ in\)
substitute
\(LA=2\pi (2.5)(8)=126\ in^{2}\)