Verified Answer :

I will use the sin (a + b) identity: 
sin (a + b) = sina cosb + cosa sinb and
here a = π/2 and b = π/7 


so sin (π/2 + π/7) 
= sin (9π / 14)

Answer:

\(\text{sin}(\frac{9\pi}{14})\).

Step-by-step explanation:

We have been given a trigonometric expression \(\text{sin}(\frac{\pi}{2})\text{cos}(\frac{\pi}{7})+\text{cos}(\frac{\pi}{2})\text{sin}(\frac{\pi}{7})\). We are asked to write our given expression as either the sine, cosine, or tangent of a single angle.

Using identity \(\text{sin}(a)\text{cos}(b)+\text{cos}(a)\text{sin}(b)=\text{sin}(a+b)\), we can rewrite our given expression.

Let \(a=\frac{\pi}{2}\) and \(b=\frac{\pi}{7}\).

Upon substituting these values in above identity, we will get:

\(\text{sin}(\frac{\pi}{2})\text{cos}(\frac{\pi}{7})+\text{cos}(\frac{\pi}{2})\text{sin}(\frac{\pi}{7})=\text{sin}(\frac{\pi}{2}+\frac{\pi}{7})\)

Upon simplifying right side of our equation, we will get:

\(\text{sin}(\frac{\pi}{2}+\frac{\pi}{7})=\text{sin}(\frac{\pi*7}{2*7}+\frac{\pi*2}{7*2})\)

\(\text{sin}(\frac{\pi}{2}+\frac{\pi}{7})=\text{sin}(\frac{7\pi}{14}+\frac{2\pi}{14})\)

\(\text{sin}(\frac{\pi}{2}+\frac{\pi}{7})=\text{sin}(\frac{7\pi+2\pi}{14})\)

\(\text{sin}(\frac{\pi}{2}+\frac{\pi}{7})=\text{sin}(\frac{9\pi}{14})\)

Therefore, our required expression would be \(\text{sin}(\frac{9\pi}{14})\).