Answer:
De-Broglie wavelength of the baseball is \(1.08\times 10^{-34}\ m\)
Explanation:
It is given that,
Mass of the baseball, m = 143 g = 0.143 kg
Velocity of the baseball, v = 95 m/h
Converting m/h to m/s
1 m/h = 0.447 m/s
Velocity of the baseball, v = 95 m/h = 42.46 m/s
De-Broglie wavelength is given by :
\(\lambda=\dfrac{h}{mv}\)
h is Planck's constant
\(\lambda=\dfrac{6.6\times 10^{-34}}{0.143\times 42.46}\)
\(\lambda=1.08\times 10^{-34}\ m\)
Hence, the De-Broglie wavelength of the baseball is \(1.08\times 10^{-34}\ m\)
