Answer:
The product of given expression \(\left(3x-7y\right)^2\) is \(9x^2-42xy+49y^2\)
Step-by-step explanation:
Given : The expression \(\left(3x-7y\right)^2\)
We have to find the product of the given expression \(\left(3x-7y\right)^2\)
Apply perfect square formula , \(\quad \left(a-b\right)^2=a^2-2ab+b^2\)
we have a = 3x and b = 7y
we get,
\(=\left(3x\right)^2-2\cdot \:3x\cdot \:7y+\left(7y\right)^2\)
Simplify, we have,
\(=9x^2-42xy+49y^2\)
Thus, The product of given expression \(\left(3x-7y\right)^2\) is \(9x^2-42xy+49y^2\)
