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lackellenico
lackellenico lackellenico
  • 30-07-2016
  • Mathematics
Answered

Show that if A^2 =0 then I-A in invertible and (I-A)^-1=I+A.

Verified Answer :

Hussain514 Hussain514
  • 02-08-2016

Let A be an nxn matrix. Show that if A^(2) = 0, then I-A is nonsingular and (I-A)^(-1) = I+A 

Note that (I - A)(I + A) 
= I(I + A) - A(I + A) 
= (I - A) - (A + A^2) 
= I - A^2 
= I - 0, since A^2 = 0 
= I. 

Hence, I - A is non singular with inverse I + A (since the inverse is unique when it does exist)

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