A guy-wire is attached to a pole for support. If the angle of elevation to the pole is 67° and the wire is attached to the ground at a point 137 feet from the base of the pole, what is the length of the guy wire (round to 2 decimal places)?. . A) 58.15 feet. . B) 143.40 feet. . C) 148.83 feet. . D) 350.62 feet
Answer: The correct option is 350.62 feets.
Step-by-step explanation:
Let the triangle Δ ABC
the length of wire = AC
Height of the pole = AB
Length between the point of attachment of wire from base of the pole = BC = 137 feets
Angle of elevation to the pole = θ = 67 °
According to trigonometry :
cosθ = \(\frac{base}{hypotenuse}\)
cos 67 ° = \(\frac{BC}{AC}\)
\(0.39=\frac{137}{AC}\)
AC = 351.28 feets \(\approx\) 351 feets.
From the given option the closest value to our answer is 350.62 feets.
Hence, the correct option is 350.62 feets.
Answer: For this diagram, the answer is D) 322.75 feet
Step-by-step explanation:
Since this is a right triangle and you know the angle and the adjacent side, use tan(x) = opp/adj
tan 67° = x/137
x = 322.75