Solve 4 log12 2 + log12 x = log12 96. Choose one answer.. a. x = 88. b. x = 80. c. x = 12. d. x = 7
\(4log_{12} 2 + log_{12} x = log_{12} 96 \\ log _{12} 2^{4} +log _{12} x = log _{12} 96 \\ log _{12} 16x = log_{12} 96\)
16 x = 96
x = 96 : 16 = 6
Answer : D ) x = 6 ( x = 7 is the wrong answer )
Answer:
Value of x is 6.
Step-by-step explanation:
Using logarithmic rules:
Solve: \(4 \log_{12} 2+\log_{12} x = \log_{12} 96\)
Apply the logarithmic rules:
\(\log_{12} 2^4+\log_{12} x = \log_{12} 96\)
\(\log_{12} 16+\log_{12} x = \log_{12} 96\)
then;
\(\log_{12} 16x = \log_{12} 96\)
Again apply the same rules:
16x = 96
Divide both sides by 6 we get;
x = 6
therefore, the value of x is 6