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A tennis player player receives a shot with the ball (.06kg) travelling horizontally at 50.0 m/s and returns the shot with the ball travelling horizontally at 40.0 m/s in the opposite direction. a) What is the impulse delivered to the ball by the tennis racquet? b) What work does the racquet do on the ball?

Verified Answer :

Let: 

m- 0.0600Kg 
v1- +50.0 m/s 
v2- -42 m/s 

a) 

momentum1 - momentum2 = impulse 
p1 - p2 = Ft 
m(v1 + v2) = Ft 
Ft = 0.54 N-s 

b) 

Work is traditionally force times distance but an easy way to get through this one is to think logically and keep your units straight: 

The racket creates an overall velocity of 90 m/s for the ball: 

W=(Ft)(V) 
W=0.54 N-s 90 m/s 
W=48.6 N-m = 48.6 J

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