Answer:
\(x=\frac{1+\sqrt{17}}{2}\) and \(x=\frac{1-\sqrt{17}}{2}\)
Step-by-step explanation:
\(x^2 - x - 4 = 0\)
To solve for x , apply quadratic formula
\(x=\frac{-b+-\sqrt{b^2-4ac}}{2a}\)
a=1 , b= -1 , c= -4
Plug in all the values in the formula
\(x=\frac{-(-1)+-\sqrt{(-1)^2-4(1)(-4)}}{2(1)}\)
\(x=\frac{1+-\sqrt{1+16}}{2}\)
\(x=\frac{1+-\sqrt{17}}{2}\)
\(x=\frac{1+\sqrt{17}}{2}\) and \(x=\frac{1-\sqrt{17}}{2}\)
