Answer:
Option D) 4.50 in3
Step-by-step explanation:
step 1
Find out the volume of the cone
The volume of the cone is
\(V=\frac{1}{3}\pi r^{2} h\)
we have
\(r=1.25\ in\)
\(h=2.75\ in\)
assume
\(\pi =3.14\)
substitute
\(V=\frac{1}{3}(3.14)(1.25^{2})(2.75)\)
\(V=4.50\ in^3\)
step 2
Find out the volume of the sphere (bubble gum)
The volume of the sphere is
\(V=\frac{4}{3}\pi r^{3}\)
we have
\(r=0.5/2=0.25\ in\) -----> the radius is half the diameter
assume
\(\pi =3.14\)
substitute
\(V=\frac{4}{3}(3.14)(0.25^{3})\)
\(V=0.07\ in^3\)
step 3
Find out the volume of the cone that can be filled with flavored ice
Sum the volumes
\(V=4.50+0.07=4.57\ in^3\)
therefore
The closest approximation of the volume of the cone that can be filled with flavored ice is 4.50 in3
