If f(x)=(e^(2x)+1)^1/2 then f'(0)=
We will first find f ( x ) using the chain rule:f ( x ) = \(\frac{1}{2 \sqrt{e ^{2x}+1 } } * 2e^{2x} = \frac{e^{2x} }{ \sqrt{e ^{2x} +1} }\)f ( 0 ) = \(\frac{e ^{0} }{ \sqrt{e^{0}+1 } } = \frac{1}{ \sqrt{2} }\)Answer: f ( 0 ) = 1/√2 ( or: √2/2 )
( x ) using the chain rule:f
( 0 ) = \(\frac{e ^{0} }{ \sqrt{e^{0}+1 } } = \frac{1}{ \sqrt{2} }\)Answer: f
