The horizontal component of the initial speed:
v x = v · cos 40° = v · 0.766
The vertical component of the initial speed:
v y = v · sin 40° = v · 0.6428. If the player is 10 m from the basket:
( 1 ) 10 = v · 0.766 · t
Net high is 1.05 m with the respect to the player ( 3.05 m - 2 m)
1.05 = - gt²/2 + v · 0.6428 · t
( 2 ) 1.05 = - 4.9 t² + v t · 0.6428
Now we have to solve a system of equations:
v = 13.05 / t ( we will put it in the second equation )
1.05 = -4.9 t² + 8.39
4.9 t² = 7.34
t ≈ 1.22 s
v = 13.05 : 1.22
Answer:
v = 10.07 m/s ( initial speed )
