Answer:
\(2\sqrt{10}\)
Step-by-step explanation:
Given equation
\(6 + 2i\\\)
Where "i" signifies an imaginary number
We know that
\(a+bi = \sqrt{(a^2 + (-b)^2)}\)-------Eq (A)
Here ,
a \(= 6\)
b\(= -2\)
Substituting the given values in equation (A), we get -
\(6+2i\\= \sqrt{(6^2+(-2)^2} \\= \sqrt{(36+4)}\\ = \sqrt{40}\\ = \sqrt{4*10} \\= 2\sqrt{10}\)
Hence, the values of equation is \(2\sqrt{10}\)
