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An acute angle θ is in a right triangle with sin θ = six sevenths. What is the value of cot θ?


Answers

7 / (sqrt 13)

(sqrt 13) / 6

6 / (sqrt 13)

(sqrt 13) / 7

Verified Answer :

konrad509

\(\sin \theta =\dfrac{6}{7}\\ \cot \theta=\dfrac{x}{6}\\ x^2+6^2=7^2\\ x^2=49-36\\ x^2=13\\ x=\sqrt{13}\\ \boxed{\cot \theta =\dfrac{\sqrt{13}}{6}}\)

frika

Consider right triangle ABC with leg BC=6, hypotenuse AB=7 and angle C such that \(\sin \angle A=\dfrac{6}{7}.\)

By the Pythagorean theorem, you can find the length of the second leg AC:

\(AC^2+BC^2=AB^2,\\AC^2+36=49,\\AC^2=13,\\AC=\sqrt{13}.\)

Use the definition of \(\cot\):

\(\cot \angle A=\dfrac{\text{adjacent leg}}{\text{opposite leg}}=\dfrac{AC}{BC} =\dfrac{\sqrt{13}}{6}.\)

Answer: \(\cot \theta=\dfrac{\sqrt{13}}{6}.\)

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