Answer:
Option D is correct.
(-1, -7)
Step-by-step explanation:
Given the equation of line: \(y+3 = 2(x-1)\) ......[1]
A.
(2, 9)
Substitute the value of x = 2 and y = 9 in [1]; we have;
\(9+3 = 2(2-1)\)
\(12= 2\) False.
Similarly, for
B.
(1, -4)
Substitute the value of x = 1 and y = -4 in [1]; we have;
\(-4+3 = 2(1-1)\)
\(-1= 0\) False.
C.
(1, 7)
Substitute the value of x = 1 and y = 7 in [1]; we have;
\(7+3 = 2(2-1)\)
\(10= 2\) False.
D.
(-1, -7)
Substitute the value of x = -1 and y = -7 in [1]; we have;
\(-7+3 = 2(-1-1)\)
\(-4= 2(-2)\)
\(-4= -4\) True
E.
(0,0)
Substitute the value of x = 0 and y = 0 in [1]; we have;
\(0+3 = 2(0-1)\)
\(3= -2\) False.
F.
(2, 1)
Substitute the value of x = 2 and y = 1 in [1]; we have;
\(1+3 = 2(2-1)\)
\(4= 2\) False.
Therefore, the only point which lies on the line described by the equation \(y+3 = 2(x-1)\) is, (-1, -7)
