find limit of (-6+x)/x^3 at x=0
\(\lim_{x \to 0} \frac{-6 + x}{x^{3}}\)\(\lim_{x \to0}\frac{-6 + x}{x^{3}} = \frac{-6 + 0}{0^{3}}\)\(\lim_{x \to 0} -\frac{-6 + x}{x^{3}} =\frac{-6}{0}\)The limit of this equation is an undefined number.
