A certain quantity grows exponentially over time. The initial quantity at t = 0 is 100. The quantity grows by a factor of 2.5%. What is the quantity at t = 5?
So the quantity of the growth is C.113.1408. I hope you are satisfied with my answer and feel fee to ask for more if you have clarification and further question. Have a nice day
Answer:
quantity after 5 years will be 113.14
Step-by-step explanation:
A certain quantity grows exponentially over time.
and the function will represent the growth will be \(f(t)=ar^{t}\)
where a = 100
and growth factor is 2.5%
So the common factor by which the growth will be = 1 + 0.025 = 1.025
\(f(t)=100(1.025)^{t}\)
After t = 5 years
f(5) = 100 (1.025)⁵
= 100 (1.1314)
= 113.14
Therefore, quantity after 5 years will be 113.14.