The ages of trees in a forest are normally distributed with a mean of 25 years and a standard deviation of 4. Approximately what percent of the trees are between 20 and 30 years old?
The percentage that the trees are between 20 and 30 years old, base on the data you have given and by graphing its information, the percentage would be 78.88%. I hope you are satisfied with my answer and feel free to ask for more
Answer:
78.88%
Step-by-step explanation:
We have been given that
\(\mu=25,\sigma=4,x_1=20,x_2=30\)
The z-score formula is given by
\(z-\text{score}=\frac{x-\mu}{\sigma}\)
For \(x_1=20\)
\(z_1=\frac{20-25}{4}\\\\z_1=-1.25\)
For \(x_2=30\)
\(z_2=\frac{30-25}{4}\\\\z_2=1.25\)
Now, we find the corresponding probability from the standard z score table.
For the z score -1.25, we have the probability 0.1056
For the z score 1.25, we have the probability 0.8944
Therefore, the percent of the trees that are between 20 and 30 years old is given by
0.8944 - 0.1056
= 0.7888
=78.88%