Simplify sine theta over square root of the quantity 1 minus sine squared theta.
Answer with explanation:
In the problem ,theta is replaced by A.
Use the following trigonometric identity to solve the problem
\(1.sin^2A+cos^2A=1\\\\2.tan A=\frac{sinA}{cosA}\)
The Given function is
\(\frac{sin A}{\sqrt{1-sin^2A}}\\\\= \frac{sinA}{\sqrt{cos^2A}}\\\\=\frac{sinA}{cosA}\\\\=tan A\)
The expression is simplified as tan θ.
A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.
The expression is given below.
\(\rm \rightarrow \dfrac{\sin \theta}{ \sqrt {1 - \sin ^2 \theta}}\)
We know
sin²θ + cos²θ = 1
Then the expression can be simplified as
⇒ sinθ /√(cos²θ)
⇒ sinθ / cosθ
⇒ tanθ
More about the triangle link is given below.
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