Yu8ryBoeight
Answered

What is the frequency of radiation emitted by a photon of light if the energy released during its transition to ground state is 3.611 × 10-15 joules? (Planck's constant is 6.626 × 10-34 joule seconds)

5.50 × 10-11 Hz

2.39 × 10-50 Hz

5.45 × 1018 Hz

1.633 × 1027 Hz

Verified Answer :

The answer is 5.45 x 1018 Hz. Good luck!

Answer:

Option (3)

Explanation:

The formula to find the energy of each photon is given by

E = h f

Where, h is the Plank's constant and f be the frequency.

\(3.611\times  10^{-15} = 6.626 \times 10^{-34} \times  f\)

f = \(5.45 \times  10^{18}\) Hz

Related Questions