Consider what you know about the relative locations of the vertex and x-intercepts of the graph of a quadratic function. Describe in detail how the quadratic formula defines these points algebraically.
Hello,
the relative locations of the vertex is (a,b)
and x-intercepts is x₀
y=k(x-a)+b
and
0=k(x₀-a)+b==>k=-b/(x₀-a)
==>y=-b/(x₀-a)*(x-a)+b
The relative positions of the vertices are (a, b)
, and the x-intercept is x₀
y = k (x-a) + b and
0 = k (x₀-a) + b ==> k = -b /. (X₀-a)
==> y = -b / (x₀-a) * (x-a) + b
The equation of a quadratic function is f (x) = ax2 + bx + c. Where a ≠ 0. Let's look at some examples of quadratic functions. f (x) = 2x2 + 4x-5; where a = 2, b = 4, c = -5. f (x) = 3x2-9; where a = 3, b = 0, c = -9.
There are three general forms of quadratic equations.
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