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Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a blue marble, not replacing it, and picking a brown marble?

Verified Answer :

There are a total of 19 marbles. 

The chance of picking a blue marble is \(\frac{7}{19}\)

Since you didn't put that marble back in, there are 18 marbles still in the bag.

The chance of picking a brown marble is \(\frac{1}{18}\)

Multiplying the two values together results with \(\frac{7}{342}\)

Airfallinout

the probability of picking a blue marble and not replacing it is 7 out of 19

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