Verified Answer :

yadvi3

In equation 1, When x = 0, y = -3 ( 0, -3)
And when y = 0, x = -3....( 3,0)
In equation 2, when x = 1, y = -4(1,-4)
and when y = 2, x = 5....(5,2)

You have to plot the points on graph paper and the solutions are where the two lines intersect.
You can use any points for x and y.

we have that

the system

\(2x+2y=-6\)

and

\(3x-2y=11\)


we know that the solution of the system is the intersection of both graphs

so

using a graph tool

see the attached figure


the solution is the point \((1,-4)\)


therefore


the answer is

the solution to the system is the point \((1,-4)\)

View image calculista