the length of one leg of an isosceles right triangle is 3 ft . what is the perimeter of the triangle
The hypotenuse is given by
\(3^{2} + 3^{2} =Hypotenuse squared
9+9= h^{2}
h= \sqrt{18}\)
Perimeter=(3+3+\(\sqrt{18}\))feet
P=6+3\(\sqrt{2} ) feet\)
Answer:
Perimeter = 6+
\(3\sqrt{2}\) ft
Step-by-step explanation:
Since given triangle is isosceles and right therefore two equals sides are the legs of right triangle given 3 and third side Hypotenuse say (x )
Using Pythagorean theorem , we get
\(x^{2} = 3^{2} +3^{2} \\ = 9 + 9 \\ = 18 \\x^2 = 18 \\\)
taking square root both sides ,we get
\(x = 3\sqrt{2}\)
Three sides of given triangles are
3 ft ,3ft and \(3\sqrt{2}\)
Perimeter is given by = sum of all three sides = 3+3+
\(3\sqrt{2}\)
= 6 + \(3\sqrt{2}\) ft