kennadir
Answered

Add. Simplify your answer. 3y^2/y+1 + 3y/y+1

A2y
B3y^2
C3y
Dy+1

Add or subtract. Simplify your answer. c+5/3c+3 − 4/3c+3

Ac/3c+3
B3c
Cc+1/3c
D1/3

Verified Answer :

dalendrk

\(\dfrac{3y^2}{y+1}+\dfrac{3y}{y+1}=\dfrac{3y^2+3y}{y+1}=\dfrac{3y(y+1)}{y+1}=3y\to\fbox{B.}\\\\\\\dfrac{c+5}{3c+3}-\dfrac{4}{3c+3}=\dfrac{c+5-4}{3c+3}=\dfrac{c+1}{3c+3}=\dfrac{c+1}{3(c+1)}=\dfrac{1}{3}\to\fbox{D.}\)

Related Questions