Answer:
\((x+4)^{2}=19\)
Step-by-step explanation:
we have
\(x^{2} +8x-3=0\)
Group terms that contain the same variable, and move the constant to the opposite side of the equation
\(x^{2} +8x=3\)
Complete the square. Remember to balance the equation by adding the same constants to each side
\((x^{2} +8x+16)=3+16\)
\((x^{2} +8x+16)=19\)
Rewrite as perfect squares
\((x+4)^{2}=19\)
