the surface area of an oil spill gets 131% larger every day, represented by the function s(x) = (1.31)x − 1. on the first day, it covered an area of 21 square meters. which function would be used to find the area of the oil spill on the 47th day?
s(x) = 21(1.31) ^(x -1)
Day 1
s(1) = 21 (1.31)^(0) = 21
Day 47
s(47) = 21(1.31)^46
Answer: 21(1.31)^46
Answer:
\(s(47)=21(1.31)^{46}\)
Step-by-step explanation:
The given equation for the scenario is,
\(s(x)=21(1.31)^{x-1}\)
where,
s(x) is the surface area of an oil spill,
x is the number days.
On the first day, it covered an area of 21 square meters.
Putting x=1, we get \(s(x)=21(1.31)^{1-1}=21(1.31)^0=21\times 1=21\)
Hence, putting x=47, we will get the surface area of the oil spill on 47th day. So
\(s(47)=21(1.31)^{47-1}\\\\=21(1.31)^{46}\\\\=5,208,335\)