A quantity b varies jointly with c and d and inversely with e. When b is 18, c is 4, d is 9, and e is 6. What is the constant of variation?


1/12

1/3

3

12

Verified Answer :

b\(\alpha\)\(\frac{cd}{e}\)
b=\(k \frac{cd}{e}\)
Where k is a constant of proportionality.
b=18, c=4,d=9, e=6
Finding the value f k,
18=\(\frac{k*4*9}{6}\)
6k=18
k=3
The equation then is;
b=\(\frac{3cd}{e}\)
The constant of variation=3

Answer:

The answer is C. 3

Step-by-step explanation: