Which of the following functions would not model exponential decay?o A) h (x) 44 0.89O B) j (x) (0.34O C) b(x) 876 (1)o D z(x)- 7 (0.999)4x-2

Which of the following functions would not model exponential decay?o A) h (x) 44 0.89O B) j (x) (0.34O C) b(x) 876 (1)o D z(x)- 7 (0.999)4x-2 class=

Verified Answer :

caylus

Hello,
1^x=1
==>b(x)=876 is not a model exponential.

Answer C

Answer:

\(b(x) = 875(1)^x\)

Step-by-step explanation:

An exponential function \(y=ab^x\) is called,

(i) Growth function : If 1 < b,

(ii) Decay function : If 0 < b < 1

\(h(x) = 44(0.89)^{2x}\)

\(\implies h(x) = 44(0.89^2)^2 = 44(0.7921)^x\)

∵ 0.7921 < 1

Hence, it is a decay function,

\(j(x) = (0.34)^{x-3}= (0.34)^{-3} (0.34)^x\implies j(x) =25.44(0.34)^x\)

∵ 0.34 < 1

Hence, j(x) is a decay function,

\(b(x) = 875(1)^x \implies b(x) =875\)

Which is a constant function,

Hence, b(x) is not an exponential decay function.

\(z(x) = 7(0.999)^{4x-2}=7(0.999)^{-2} (0.999)^x=7.014(0.999)^x\)

∵ 0.999 < 1

Hence, z(x) is a decay function.