simplify each radical expression.√8+√28
\(\sqrt{8} + \sqrt{28}\)=\(\sqrt{4*2} + \sqrt{4*7}\)=2\(\sqrt{2} +2 \sqrt{7}\)
Solutions \(\sqrt{8}+ \sqrt{28} Find the number that is multiplied by 4 and is equal to 8 and 28. = \sqrt{4*2} + \sqrt{4*7} \sqrt[2]{2} + \sqrt[2]{7}\)
