\(x^{2} + y^{2} =26
x-y=6
x=y+6
Replacing in equation;
(y+6[tex] )^{2}\)+\(y^{2}\)=26
\(y^{2} +12x+36+ y^{2} =36\)
=\(2y^{2} +12x+36-26=0\)
=\(2y^{2} +12x+10=0\)
Product = 12
Sum= 10
factoring;
2\(y^{2}\)+2y+10y+10=0
2y(y+1)+10(y+1)=0
(2y+10)(y+1)=0
y=-1 or 2y=-10
y=-5
x=y+6
When y =-1
x=-1+6
x=5
when y =-5
x=-5+6
x=+1
