Simplify square root parenthesis 1 minus cosine theta parenthesis times parenthesis 1 plus cosine theta parenthesis divided by cosine squared theta A. square root sine theta B. ±sin Θ C. ±cos Θ D. |tan Θ|
The answer is D. |tan Θ|
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Answer:
option D is correct.
Step-by-step explanation:
we are given the function \(\sqrt{\frac{(1-\cos \theta )(1+\cos \theta )}{\cos ^2\theta }}\)
we know that the expansion is given by \((1-\cos \theta )(1+\cos \theta )=1-\cos ^2\theta =\sin ^2\theta\)
so \(\sqrt{\frac{(1-\cos \theta )(1+\cos \theta )}{\cos ^2\theta }}=\sqrt{\frac{\sin ^2\theta }{\cos ^2\theta }}=\sqrt{\tan ^2\theta }=|\tan \theta |\)
Hence, option D is correct.