Estimate the heat of neutralization of H3PO4 in kJ/mol given these data: Heat transferred = 2.2 x 102 J Moles of H3PO4 = 1.5 x 10−3 mol Moles of NaOH = 5.0 x 10−3 mol
write out the balance equation
3NaOh+H3PO4->Na3PO4+3H2O
You are given everything needed to calculate
q=heat transfer=2.210^2,
H3PO4 moles= 1.510^-3,
NaOH moles=5.010^-3
equation is deltaHneutraliztion=q/Moles of limiting reagent
H3PO4 is limiting reagent because lowest moles, and is used up first
Now plug in variables
DeltaH=2.210^2(1.5*10^3)= 146.67kj/mole
Notice we had to convert J to kj,
1.) write out the balance equation
3NaOh+H3PO4->Na3PO4+3H2O
2.) You are given everything needed to calculate
q=heat transfer=2.210^2, H3PO4 moles= 1.510^-3, NaOH moles=5.010^-3
3.) equation is deltaHneutraliztion=q/Moles of limiting reagent
H3PO4 is limiting reagent because lowest moles, and is used up first
4.) Now plug in variables
DeltaH=2.210^2(1.5*10^3)= 146.67kj/mole
Notice we had to convert J to kj,