Verified Answer :

write out the balance equation
3NaOh+H3PO4->Na3PO4+3H2O
You are given everything needed to calculate
q=heat transfer=2.210^2,
H3PO4 moles= 1.5
10^-3,
NaOH moles=5.010^-3
equation is deltaHneutraliztion=q/Moles of limiting reagent
H3PO4 is limiting reagent because lowest moles, and is used up first
Now plug in variables

DeltaH=2.2
10^2(1.5*10^3)= 146.67kj/mole

Notice we had to convert J to kj,

1.) write out the balance equation
3NaOh+H3PO4->Na3PO4+3H2O

2.) You are given everything needed to calculate
q=heat transfer=2.210^2, H3PO4 moles= 1.510^-3, NaOH moles=5.010^-3 


3.) equation is deltaHneutraliztion=q/Moles of limiting reagent
H3PO4 is limiting reagent because lowest moles, and is used up first 


4.) Now plug in variables
DeltaH=2.2
10^2(1.5*10^3)= 146.67kj/mole
Notice we had to convert J to kj,