ale5monalice7
Answered

Josiah is taking his friends to the movies. Each ticket costs $10, and popcorn is $5 a bag. There is a $3 service fee for the entire purchase. He has $75. If he buys 4 tickets, how many bags of popcorn can he buy? If x = number of tickets and y = number of bags of popcorn, derive the inequality to be used to answer the problem.

Verified Answer :

Each ticket costs $10. He bought "x" tickets. Ticket cost = 10x

Each bag of popcorn costs $5.
He bought "y" bags of popcorn.
Popcorn cost = 5y
Service fee: $3

Total cost = 10x + 5y + 3 <= $75 is the inequality.

10x + 5y <= 72
If x = 4,
then 40 + 5y <= 72

5y <= 32

y <= 6.4

So y = 6 bags of popcorn.

Josiah can buy 6 more popcorn bags. 

The solution is as follows:
10x + 5y + 3 ≤ 75

if x = 4, the inequality will look like this:
10(4) + 5y + 3 ≤ 75
43 +5y ≤ 75
5y ≤ 32
y ≤ 6.4 or 6

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

 

 

 

Related Questions