What is the volume of 0.200 mol of an ideal gas at 200 kPa and 400 K? A. 0.83 L B. 3.33 L C. 5.60 L D. 20.8 L
Since it is stated that it is an ideal gas, we use the ideal gas equation to solve the volume of this gas sample. The ideal gas equation is expressed as:
PV = nRT
V = nRT / P
V = 0.200 (8.314) (400) / 200x10^3
V = 3.33 x 10^-3 m³ or 3.33L
Therefore, the correct answer is option B.
The volume of a 0.200 mol of an ideal gas at 200 kPa and 400 K is 3.33L. Details about ideal gases can be found below.
The volume of an ideal gas can be calculated using the following formula:
PV = nRT
Where;
1.97 × V = 0.2 × 0.0821 × 400
1.97V = 6.57
V = 6.57 ÷ 1.97
V = 3.33L
Therefore, the volume of a 0.200 mol of an ideal gas at 200 kPa and 400 K is 3.33L.
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