Look at this linear equation. 3x + 5y = 30 Which of the following equations can be used to solve for y in the linear equation above? y = - x + 30 y = 3x + 6 y = - x + 6 y = x + 30

Verified Answer :

y=-
\(\frac{3}{5} x + 6\)


Answer:

\(y=-\frac{3}{5}x+6\)

Step-by-step explanation:

The given linear equation is

\(3x+5y=30\)

We need to solve the above equation for y.

Using subtraction property of equality, subtract 3x from both sides.

\(3x+5y-3x=30-3x\)

\(5y=30-3x\)

Using division property of equality, divide both sides by 5.

\(y=\frac{30-3x}{5}\)

\(y=\frac{30}{5}-\frac{3x}{5}\)

\(y=6-\frac{3}{5}x\)

Arrange the terms.

\(y=-\frac{3}{5}x+6\)

Therefore, the required equation is \(y=-\frac{3}{5}x+6\).