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alisset06 alisset06
  • 24-07-2016
  • Mathematics
Answered

find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule A (n) =-6+(n-1)(6)

Verified Answer :

dalendrk
dalendrk dalendrk
  • 31-07-2016

a(n) = -6 + (n - 1)(6) = -6 + 6n - 6 = 6n - 12

a(1) = 6(1) - 12 = 6 - 12 = -6

a(4) = 6(4) - 12 = 24 - 12 = 12

a(10) = 6(10) - 12 = 60 - 12 = 48

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Anonymous Anonymous
  • 13-08-2019

Answer with explanation:

  General term of arithmetic sequence and first, fourth, and tenth terms are

\(A_{n}=-6 +6(n-1)\\\\A_{1}= -6 +6(1-1)\\\\A_{1}=-6\\\\A_{4}=-6+6(4-1)\\\\A_{4}=-6+6 \times 3\\\\A_{4}=-6+18\\\\A_{4}=12\\\\A_{10}=-6+6 \times (10-1)\\\\A_{10}=-6+6 \times9\\\\A_{10}=-6+54\\\\A_{10}=48\)

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