What is the ratio of the area of ABC to the area of ABD?
What is the ratio of the area of ABC to the area of ABD?
area ABD = 1612/2
area ABC = 912/2
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so the ratio of the area ABC to the area of ABD = (912/2)/(1612/2) =
= 9/16
hope helped
The ratio of the area of the triangle ABC and ABD will be \(\dfrac{9}{16}\)
The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the triangle in a two-dimensional plane is called as the area of the triangle.
The two areas will be calculated as:-
Area ABD = ( 1 / 2 ) x 16 x 12
Area ABC = (1 / 2 ) x 9 x 12
So the ratio of the area ABC to the area of ABD will be
= [ ( 1 / 2 ) x 16 x 12 ] ÷ [ (1 / 2 ) x 9 x 12 ]
= 9 / 16
Therefore the ratio of the area of the triangle ABC and ABD will be \(\dfrac{9}{16}\)
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