Helium has a density of 1.79 x 10-4 g/mL at standard temperature and pressure. A balloon has a volume of 6.3 liters. Calculate the mass of helium that it would take to fill the balloon. Be sure to follow significant figure rules when calculating the answer.
By definition, the density is given by:
\(D = \frac{m}{V}
\)
Where,
m: Helium mass
V: helium volume
Clearing the mass we have:
\(m = VD
\)
Transforming the volume to milliliters we have:
\(V = (6.3) * (1000) = 6300 mL
\)
Then, replacing values:
\(m = (6300) * (1.79 * 10 ^ {-4})
m = 1.1277 g
\)
Answer:
The mass of helium that would take to fill the balloon is:
\(m = 1.1277 g\)
Answer:
The correct answer is 1.1 grams.
Carlosego failed to round it, sorry for his mistake.