Answer : The volume of liquid mixture \(CHCl_3\) and \(CHBr_3\) are, 11.73 ml and 8.27 ml respectively.
Explanation : Given,
The overall density of mixture = \(2.07g/cm^3=2.07g/ml\)
The density of \(CHCl_3\) = 1.492 g/ml
The density of \(CHBr_3\) = 2.890 g/ml
Total volume of liquid mixture = 20 ml
Let us assumed that the volume of \(CHCl_3\) = X ml and the volume of \(CHBr_3\) = Y ml
So, the sum of volumes is equal to the total volume of mixture required.
\(Xml+Yml=20ml\) ...............(1)
As we have to determine the density of the liquid mixture. So, the mass would be,
\(Density\times Volume=Mass\)
The equation will be :
\(\text{Density of }CHCl_3\times \text{Volume of }CHCl_3+\text{Density of }CHBr_3\times \text{Volume of }CHBr_3=\text{Density of mixture}\times \text{Volume of mixture}\)
\(1.492g/ml\times (Xml)+2.890g/ml\times (Yml)=2.07g/ml\times (20ml)\) ........(2)
Now equating both the equation 1 and 2, we get the
X = 11.73 ml
Y = 8.27 ml
Therefore, the volume of liquid mixture \(CHCl_3\) and \(CHBr_3\) are, 11.73 ml and 8.27 ml respectively.
