what is the equation of the line that passes through the points (−1, 3) and (1, 11)? (5 points) 4x − y = 1 4x y = 1 x − 4y = −13 4x − y = −7
find slope
(y2-y1)/(x2-x1) is slope
(11-3)/(1-(-1))=8/2=4
y=4x+b
input a point
(1,11)
x=1
y=11
11=4(1)+b
11=4+b
minus 4 from both sides
7=b
the equatin is
y=4x+7
the closest one
minus 4x from both sides
y-4x=7
times everybody by -1
4x-y=-7
last choice is answer
Find gradient;
m=\(\frac{change in y}{change in x}\)
m=\(\frac{11-3}{1--1}\)
m=\(\frac{8}{2}\)
m=4
Equation line;
y=4x+c
Replacing for x and y;
3=4(-1)+c
3=-4+c
c=7
y=4x+7