Verified Answer :

f(2a)=35
35=(2a)^2-1
35=4a^2-1
minus 35 from both sidse
0=4a^2-36
facor out 4
0=4(a^2-9)
factor differece of 2 perfect squares
0=4(a-3)(a+3)
set to zero
a-3=0
a=3

a+3=0
a=-3


a=-3 or 3

The values of a function are gotten from the input variables

The values of a could be 3 or -3

We have:

\(f(x) = x^2 - 1\)

Substitute 2a for x

\(f(2a) = (2a)^2 - 1\)

Expand

\(f(2a) = 4a^2 - 1\)

Substitute 35 for f(2a)

\(f(2a) = 4a^2 - 1 =35\)

So, we have:

\(4a^2 - 1 =35\)

Add 1 to both sides

\(4a^2 =35+1\)

\(4a^2 =36\)

Divide both sides by 4

\(a^2 = 9\)

Take square roots

\(a = \±3\)

Hence, the values of a could be 3 or -3

Read more about functions at:

https://brainly.com/question/21797759