Answer: The radiation has a frequency of \(4.43\times 10^{9}Hz\) and is a type of radio wave.
Explanation:
The equation given by Planck's follows:
\(E=h
u\)
where,
E = energy of the light = \(2.93\times 10^{-25}J\)
h = Planck's constant = \(6.62\times 10^{-34}Js\)
\(u\) = frequency of light = ?
Putting values in above equation, we get:
\(2.93\times 10^{-25}J=6.62\times 10^{-34}Js\times
u\\\\
u=\frac{2.93\times 10^{-25}J}{6.62\times 10^{-34Js}}=4.43\times 10^{9}Hz\)
The relation between frequency and wavelength is given as:
\(u=\frac{c}{\lambda}\)
where,
c = the speed of light = \(3\times 10^8m/s\)
\(u\) = frequency of radiation = \(4.43\times 10^{8}s^{-1}\)
\(\lambda\) = wavelength of the radiation = ?
Putting values in above equation, we get:
\(4.43\times 10^{8}s^{-1}=\frac{3\times 10^8m/s}{\lambda}\\\\\lambda=\frac{3\times 10^8m/s}{4.43\times 10^8}s^{-1}}=0.677m\)
The radiation having wavelength 0.677 m belongs to radio waves.
Hence, the radiation has a frequency of \(4.43\times 10^{9}Hz\) and is a type of radio wave.
