ashkaputrilma
Answered

The equilibrium constant is given for one of the reactions below. Determine the value of the missing equilibrium constant.

2 HD(g) ⇌ H2(g) + D2(g)

Kc = 0.28


6 H2(g) + 6 D2(g) ⇌ 12 HD(g)

Kc = ?

A0.00048
B1.2
C1.62
D2075
E0.81

Verified Answer :

meerkat18

given the original equation of 2 HD(g) ⇌ H2(g) + D2(g)  with Kc = 0.28 and asked for the kc of the equation 6 H2(g) + 6 D2(g) ⇌ 12 HD(g), we can see that the equation 1 is reversed and multiplide by 6. in this case, the reverse means kc is equal to 1/0.28 and that the multiplication by 6 raises the new kc to 6. the new kc is equal to D. 2075

Blitztiger

The equilibrium constant is equal to concentration products raised to their stoichiometric coefficients, divided by the same for the reactants.

For the first reaction: \(K_c=\frac{[H_2][D_2]}{[HD]^2}=0.28\)

For the second reaction: \(K_c=\frac{[HD]^{12}}{[H_2]^6[D_2]^6}=(\frac{[H_2][D_2]}{[HD]^2})^{-6}=(0.28)^{-6}=2075\)
This is choice D.

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