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A 10.0 gram piece of metal is placed in an insulated calorimeter containing 250.0 g of water initially at 20.0°C. If the final temperature of the mixture is 25.0°C, what is the heat change of water?

A5230 J
B−5230 J
C209 J
D−209 J
E5440 J

Verified Answer :

meerkat18

The heat change of water is calculated through the equation,
                                H = m(cp)dT
where H is heat, m is mass, cp is the specific heat, and dT is the change is temperature. Substituting the known values,
                               H = (250 g)(4.18 J/g°C)(25°C - 20°C) = 5255 J
The nearest value to this is letter A. 5230 J.

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