The energy from radiation can be used to cause the rupture of chemical bonds. A minimum energy of 242 kJ/mol is required to break the chlorine–chlorine bond in Cl2. Determine the longest wavelength of radiation that possesses the energy to break the bond.

The question ask to determine the longest wavelength of radiation that possesses the energy to break the bond and the minimum energy of 242kj/mol is required to break the chlorine-chlorine bond so the energy would be that the minimum wave length is 495nm and the high wavelength to it is the color green end of its wave

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Tringa0 Tringa0 · Answer 2 · 2019-10-15T05:42:58-04:00

Answer:

The longest wavelength of radiation is 494.6 nm that will possess the energy to break the bond.

Explanation:

Energy required to break 1 mol of Cl-Cl bond = 242 kJ =242000 J

1kJ = 1000 J

1 mol = \(6.022\times 10^{23}\) atoms/particles/ molecules

Energy required to break 1 of Cl-Cl bond = E

\(E=\frac{242000 J}{6.022\times 10^{23}}=4.0186\times 10^{-19} J\)

Wave length of the radiation with energy E.

\(E=\frac{hc}{\lambda }\)

h = Planck's constant

c = speed of the light

\(\lambda = \frac{6.626\times 10^{-34} J s\times 3\times 10^8 m/s}{4.0186\times 10^{-19} J}\)

\(\lambda = 4.946\times 10^{-7} =494.6 nm\)

The longest wavelength of radiation is 494.6 nm that will possess the energy to break the bond.