Verified Answer :

konrad509

\(h=2d=2\cdot2r=4r\\ V=\dfrac{1}{3}\pi r^2 h\\ V=\dfrac{1}{3}\pi r^2 \cdot4r\\ V=\dfrac{4}{3}\pi r^3\)

meerkat18

If the height is twice the diameter of the base then, it is four times the radius. Let r be the radius. With this representation, the height of the base is 4r. The volume (V) of the pyramid is calculated through the equation,
                            V = πr²h/3
Substituting the correct variables,
                              V = 4πr³/3

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