Answer:
The correct option is 1.
Step-by-step explanation:
The given quadratic equation is
\(x^2+bx+5=0\)
A quadratic equation \(ax^2+bx+c=0\) have to real solution if the value of discriminant is garter than 0.
\(b^2-4ac>0\)
\(b^2-4(1)(5)>0\)
\(b^2-20>0\)
Add 20 on both the sides.
\(b^2>20\)
It is possible if
\(b<-\sqrt{20}, b>\sqrt{20}\)
\(b<-4.472, b>4.472\)
Since -5<-.4.472, therefore option 1 is correct.
