evaluate C(8,3)=____
\(C(8,3)=\dfrac{8!}{3!5!}=\dfrac{6\cdot7\cdot8}{2\cdot3}=7\cdot8=56\)
The evaluated value of C(8,3) is "56"
\(\to \bold{C(8,3)}\)
Using formula:
\(\bold{^nC_r=\frac{n!}{n!(n-r)!}}\)
\(\to {^8C_3=\frac{8!}{3!(8-3)!}}\\\\\)
\(=\frac{8!}{3!(5)!}\\\\=\frac{8 \times 7 \times 6 \times 5!}{3!\times 5!}\\\\=\frac{8 \times 7 \times 6 \times 5!}{3\times 2 \times 1 \times 5!}\\\\={8 \times 7}{}\\\\=56\\\)
Therefore, the final answer is "56".
Find out more information about the Combination here:
https://brainly.com/question/24442374