Verified Answer :

\(C(8,3)=\dfrac{8!}{3!5!}=\dfrac{6\cdot7\cdot8}{2\cdot3}=7\cdot8=56\)

The evaluated value of C(8,3) is "56"

Evaluation:

\(\to \bold{C(8,3)}\)

Using formula:

\(\bold{^nC_r=\frac{n!}{n!(n-r)!}}\)

\(\to {^8C_3=\frac{8!}{3!(8-3)!}}\\\\\)

          \(=\frac{8!}{3!(5)!}\\\\=\frac{8 \times 7 \times 6 \times 5!}{3!\times 5!}\\\\=\frac{8 \times 7 \times 6 \times 5!}{3\times 2 \times 1 \times 5!}\\\\={8 \times 7}{}\\\\=56\\\)

Therefore, the final answer is "56".

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